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1996-08-06
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Path: solon.com!not-for-mail
From: tanmoy@qcd.Lanl.GOV (Tanmoy Bhattacharya)
Newsgroups: comp.std.c,comp.lang.c.moderated
Subject: Re: Integral promotion.
Date: 17 Feb 1996 11:53:29 -0600
Organization: Los Alamos National Laboratory
Sender: clc@solutions.solon.com
Approved: clc@solutions.solon.com
Message-ID: <4g54mp$agm@solutions.solon.com>
References: <4fstj7$2l6@solutions.solon.com> <4fu835$9de@solutions.solon.com>
<4fvgrm$dv9@solutions.solon.com> <4g28hr$qko@solutions.solon.com>
NNTP-Posting-Host: solutions.solon.com
In article <4g28hr$qko@solutions.solon.com> thads@csn.net (Thad Smith)
writes:
<snip>
In article <4fvgrm$dv9@solutions.solon.com>, msb@sq.com wrote:
>Oh dear, I have to correct Chris Torek (torek@bsdi.com).
>Thus even in ANSI C, if this function is called this way:
>
> extern short p, q, r, test(short,short);
> r = test(p,q);
>
>the values from p and q are still converted from short to int and back
>to short.
I find nothing in the Standard that states that the arguments undergo
integral promotions before being assigned to the function parameters.
The way I read the standard (6.2.1.1):
``A char, a short int, or an int bit-field, or their signed or unsigned
varieties, or an enumeration type, may be used in an expression
wherever an int or unsigned int may be used. ...< describing integral
promotions >... these are called integral promotions.''
Seems to imply that whenever a value of type `int' is a possibility,
integral promotions always take place. Without enum types, I don't see
how this matters in a function call, as long as implementation defined
behaviour is reasonable (i.e. signed char->int->short is same as
signed char->short etc.)
For enums, I am confused. If an enum type is compatible with `long',
does integral _promotion_ narrow it to an int or unsigned int :-)?
Cheers
Tanmoy
--
tanmoy@qcd.lanl.gov(128.165.23.46) DECNET: BETA::"tanmoy@lanl.gov"(1.218=1242)
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